Chapter 19 Electrochemistry

P. 595 Section Review
2. a. reduction b. oxidation c. oxidation d. reduction e. reduction f. oxidation g. reduction h. reduction
3. a. redox b. redox c. not redox d. redox e. not redox
4. a. O-2 is oxidized to O2 ; N+5 is reduced to N+3
b. H2 is oxidized to O2 ; Cu2 is reduced to Cu
d. H2 is oxidized to H ; Cl2 is reduced to Cl
5. a. Three electrons are lost in the oxidation half-reaction; Three electrons
are gained in the reduction process. The balanced equation has a charge of 3+
on both sides.
b. There are 3 mol of Na and 1 mol o Al on both sides of the equation.
c. The number of electrons lost equals the number of electrons gained, so
they cancel out in the overall equation.

6 a. yes, b. yes, c. no d.yes, e. no


Problems / Concepts P. 618
1. a. Oxidation causes atoms or ions to attain a more positive oxidation state
and lose electrons. Reduction causes atoms or ions to attain a more negative
oxidation state and gain electron.
b. Oxidation: Na--> Na+ + e-
Reduction: Cl2+2e- ? 2Cl-

2. a, b, c, f, g, I

3. Equation Oxidized Reduced
a Na Cl2
b C O2
c O-2 H+1
f O-2 Cl+5
g H2 Cl2
I Zn Cu2+

p. 618
12.
a. oxidation K --> K+ + e-
b. reduction: S + 2e- --> S 2-
c. oxidation: Mg -->Mg 2+ + 2e-
d. oxidation: 2F- -->F2 + 2e-
e. oxidation: H2 --> 2H+ + 2e-
f. reduction: O2 + 4e- --> 2O2-
g. reduction: Fe3+ + e- -->Fe2+
h. oxidation: Mn2+ -->MnO4- + 5e-

12. 13.
a. nonredox
b. redox
c. nonredox

15.
a. 0
H2

b. +1 2
H2O

c.

0
Al

d.

+2 2
MgO

e.

+3 2
Al2S3

f.

+1+5 2
HNO3

g.

+1+6 2
H2SO4

h.

+2 2+1
Ca(OH)3

i.

+2 +5-2
Fe(NO3)2

j.

0
O2


More problems: Chapter 19 p.618 #'s 2, 5a.b.c., 6a.b.c., 12a.b.c.d.,15a.b.c.d.e., 19, 20, 22

2. a, b, c, f, g, i,
5.
a. strongest: Ca Weakest Cl-
b. strongest Al weakest br-
c. strongest na, weakest F-
6. a. yes
b. yes
c. no

12. a. oxidation:K ---> K+ + e-
b. reduction: S + 2e- --->S2-
c. oxidation: Mg ---> Mg2+ + 2e-
d. oxidation: 2F- ---> F2+ 2e-
15. a. 0
H2
b. +1 -2
H2O
c. 0
Al
d. +2 -2
MgO
e. +3 -2
Al2S3

19. a. 2Ag+ + Cu ---> 2Ag + Cu2+
b. Co2+ + Cd --> Co + Cd2+
c. 2Na + Ni2+ ---> 2 Na+ +Ni
d. Br2 + 2I- ---> 2Br- + I2

20. a. +0.46V
b. +0.12V
c. +2.45V
d. +0.53V

21. a. +0.53 v, b.-2.20 v, c. no change


22. Ni+2Ag+ ---> Ni2+2Ag
E^0 = 0.26V = 0.80 V = +1.06V

nickel dissolves, solid silver forms

27. a. spont. b, spont. c. not spont. d. spontaneous